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Question #3dc90

1 Answer

Mar 17, 2017

# = -(1)/(2y^2) + C#

Explanation:

Use the power rule:

#int \ y^n \ dy = (y^(n+1))/(n+1) + C#

Here you have:

#int \ 1/y ^3 \ dy = int \ y ^ (-3) \ dy = (y^(-3+1))/(-3+1) + C#

# = (y^(-2))/(-2) + C#

# = -(1)/(2y^2) + C#

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