Question #e45ff

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Answer 1 · 2017-10-08T06:52:15

Here

Distance traveled in first phase $s_1=150"miles"$

time of journey in first phase $t_1=3hr$

Distance traveled in 2nd phase $s_2=0"miles"$

time of journey in 2nd phase $t_2=0.5hr$

Distance traveled in 3rd phase $s_3=100"miles"$

time of journey 3rd phase $t_3=1.50hr$

So average speed

$"Total distance traveled"/"Total time taken"$

$=(s_1+s_2+s_3)/(t_1+t_2+t_3)$

$=(150+0+100)/(3+0.5+1.5)"miles/hr"$

$=50"miles/hr"$