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Question #ef3ef

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Answer 1 · 2017-03-21T00:39:15

I got $9.9 \times 10^{- 35} m$ $9.9xx10^-35m$ too small to be detected by any human mean.

Explanation:

De Broglie waelength $λ$ $lambda$ is given as:
$λ = \frac{h}{p}$ $lambda=h/p$
]Where:
$h = 6.63 \times 10^{- 34} J s$ $h=6.63xx10^-34Js$ is Planck's Constant;
$p = m v$ $p=mv$ is the linear momentum.
We have (after changing into $k g$ $kg$ and $\frac{m}{s}$ $m/s$ ):
$λ = \frac{6.63 \times 10^{- 34}}{0.145 \cdot 46.1} = 9.9 \times 10^{- 35} m$ $lambda=(6.63xx10^-34)/(0.145*46.1)=9.9xx10^-35m$

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