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Answer 1 · 2017-12-28T10:18:48

The speed is $=6.4ms^-1$ . The flow rate is $=16.29m^3h^-1$

The flow rate $Q$ is constant

$Q=v_1A_1=v_2A_2$

The speed $v_1=1.6ms^-1$

The cross section area $A_1=pid_1^2/4=pi*(0.06)^4/4m^2$

The cross section $A_2=pid_2^2/4=pi*0.03^2/4 m^2$

$pi*0.06^2/4*1.6=pi0.03^2/4*v_2$

$v_2=0.06^2/0.03^2*1.6=6.4ms^1$

The flow rate is

$Q=pi*0.06^2/4*1.6=0.0045m^3s^-1=16.29m^3h^-1$