Solve for #n#, #(-1/2+ iota sqrt(3)/2)^3 + (-1/2-iota sqrt(3)/2)^(2n)=2# ?
2 Answers
Explanation:
We have to evaluate
As
using De Moivre's Theorem
=
and
=
Therefore
where
i.e.
and
Explanation:
We will using the complex number exponential representation
So
then we have
or
but
then