Question #58423

1 Answer
SCooke
Mar 11, 2017

52.7g NaCl

Explanation:

First convert the given quantities of compounds to moles. Then apply the balanced equation. 50g #FeCl_3# is 50/161 = 0.31 mole (you didn’t specify Fe(II) or Fe(III)). 50g #Na_3PO_4# is 50/164 = 0.30 mole (Specific form also not specified).

#FeCl_3# + #Na_3PO_4# → #FePO_4# + #3NaCl#

So, we have almost equal molar quantities of each reactant. The reaction equation shows that one mole of #FeCl_3# reacts with one mole of #Na_3PO_4#. The maximum products that can be formed are one mole of #FePO_4# and three moles of NaCl for every one mole of #FeCl_3# . This reaction would produce 0.30 * 3 = 0.9 moles of sodium chloride.
0.9 mol * 58.5g/mol = 52.7g NaCl.

Related questions
See all questions in Limiting Reagent
Impact of this question
2229 views around the world
You can reuse this answer
Creative Commons License