Question #dcd39

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Question #dcd39

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Answer 1 · 2017-03-11T04:50:13

The free energy change $DeltaG$ of a chemical reaction is related with Enthalpy change $DeltaH$ , Entropypy change $DeltaS$ and the absolute temperature $T$ of the reaction as follows

$DeltaG=DeltaH-T DeltaS$

The combustion reaction of hydrocarbon exothermic one.
So $DeltaH <0$ again as per given balanced equation the number of moles of gaseous product (12moles) is greater than that of gaseous reactants (9moles). So $DeltaS>0$ and $T>0$

So as a whole RHS $DeltaH-T DeltaS<0$

Hence the free energy change of the reaction

$DeltaG<0->"The reaction is spontaneous"$

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Question #dcd39

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