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Question #d280e

1 Answer

Apr 26, 2017

$1000m$

Explanation:

Distance traveled $s$ in time $t$ . Applicable kinematic equation is
$s=ut+1/2at^2$
where $a$ is acceleration and $u$ is initial velocity.

Car a
$s_a=0xx60+1/2(0.75)(60)^2$
$s_a=1350m$

Car b
$s_b=0xx60+1/2(0.25)(60)^2$
$s_a=450m$

Difference is $=1350-450=900m$
When cars started Car a was ahead of Car b by $=100m$
After $1min$ Car a is ahead of Car b by $=900+100m=1000m$

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