Question #bc6e9
1 Answer
(1). Amount of heat energy
#Q=msDeltaT#
where#s# is specific heat capacity of the material of sample.
For two blocks one of copper and other of iron, are of same mass, and are raised through same temperature. We see that amount of heat required is directly proportional to specific heat capacity.
#Qprops#
specific heat capacity of copper
specific heat capacity of iron
(2). Assuming that iron block in (1) above is immersed into
Let the final temperature of water be
Heat gained by water
Final temperature of iron block is also same.
Equating heat gained to heat lost we get
.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-
Alternatively
Let final temp of iron-water mixture be
Heat gained by water
Heat lost by iron block
Heat gained by water
Rise in temperature of water