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Question #2258a

1 Answer

Aug 14, 2017

#f# is not continuous at #-4# and at #1#

Explanation:

#f# is continuous at every #x# in its domain. The domain is all real #x# where the denominator is not #0#.

So, #f# is not continuous at the solutions to

#x^2+3x-4# which is at #-4# and at #1#

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