Question #2258a Calculus Limits Classifying Topics of Discontinuity (removable vs. non-removable) 1 Answer Jim H Aug 14, 2017 #f# is not continuous at #-4# and at #1# Explanation: #f# is continuous at every #x# in its domain. The domain is all real #x# where the denominator is not #0#. So, #f# is not continuous at the solutions to #x^2+3x-4# which is at #-4# and at #1# Answer link Related questions How do you find discontinuity algebraically? How do you find discontinuity of a piecewise function? How do you find discontinuity points? How do you find the discontinuity of a function? How can you remove a discontinuity? How do i find discontinuity for a function? How do you find a removable discontinuity for a function? How do you find the discontinuity of a rational function? What does discontinuity mean? What does discontinuity mean in math? See all questions in Classifying Topics of Discontinuity (removable vs. non-removable) Impact of this question 1499 views around the world You can reuse this answer Creative Commons License