Question #64bf1

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Question #64bf1

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Answer 1 · 2017-03-03T11:04:53

By Brønsted–Lowry acid–base theory, a species formed by the reception of a proton $H^{∣}$ $H^|$ by a base is a conjugate acid . Again the species formed by leaving a proton by an acid is a conjugate base.

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So to get conjugate acid from a base we are to add one proton $(H^{+})$ $(H^+)$ to it.
Hence by adding proton $(H^{+})$ $(H^+)$ to $H S O_{4}^{-}$ $HSO_4^-$ we will get the conjugate acid of the given base $H S O_{4}^{-}$ $HSO_4^-$ and it is obviously $H_{2} S O_{4}$ $H_2SO_4$

$H S O_{4}^{-} + H^{+} \to H_{2} S O_{4}$ $HSO_4^(-) + H^+ ->H_2SO_4$

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Question #64bf1

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