Question #c4774

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Answer 1 · 2017-03-02T17:29:03

For violet $sf(theta=41^@)$

For blue $sf(theta=48.8^@)$

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For constructive interference to occur, the path difference must be an integral number of wavelengths.

This is AC on the diagram.

$:.$ $sf(sintheta=(nlambda)/d)$

There are 800 lines in 1 mm.

$:.$ $sf(d=1/800=1.25xx10^(-3)color(white)(x)"mm")$

$sf(d=1.25xx10^(-6)color(white)(x)"m")$

For violet light when $sf(n=2)$ :

$sf(sintheta=(2xx410xx10^(-9))/(1.25xx10^(-6))=0.656)$

$sf(theta=41^@)$

For blue light when $sf(n=2)$ :

$sf(sintheta=(2xx470xx10^(-9))/(1.25xx10^(-6))=0.752)$

$sf(theta=48.8^@)$