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If #5^(x+2)=4#, find #x#?

1 Answer

Shwetank Mauria

Mar 14, 2017

#x=-1.1386#

Explanation:

As #5^((x+2))=4#

#(x+2)log5=log4#

i.e. #x+2=log4/log5=0.60206/0.69897#

i.e. #x+2=0.8614#

and hence #x=0.8614-2=-1.1386#

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