What is the conjugate acid of #"iodide ion"#, #I^-#?

1 Answer
anor277
Feb 27, 2017

The conjugate acid of #I^-# is #HI#.............

Explanation:

The conjugate base of any acid is the original acid LESS a proton, i.e. #H^+#. And the conjugate acid of any base is the original base PLUS a proton. As in all descriptions of chemical reactivity, both #"MASS"# and #"CHARGE"# are conserved.

And thus the conjugate acid of #"iodide anion"# is #"hydroiodic acid"#.

For any acid, to find the conjugate base, simply remove a proton, and conserve mass and charge. To find the conjugate acids, simply add a proton, and likewise conserve mass and charge.

What are the conjugate acids of #NO_3^-#, #HSO_4^-#, #SO_4^(2-)#, #HPO_4^(2-)#, #MnO_4^-#, #ClO_4^-##?#

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