Question #5c303

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Answer 1 · 2017-02-28T12:36:35

Volume of carbon dioxide is #=22.4*0.5=11.2dm^3#

The reaction is

#Na_2CO_3+2HCl->2NaCl+CO_2+H_2O#

One mole of sodium carbonate is

#=(2*23)+12+(3*16)=46+12+48=106g#

1 mole of sodium carbonate will liberate #22.4dm^3# of carbon dioxide

Here, we have

#n=53/106=0.5#mole

Volume of carbon dioxide is #=22.4*0.5=11.2dm^3#