Question #1699a

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Answer 1 · 2017-02-27T12:24:45

$triangle G "of change" = -144750J = -144.75kJ$

Balance the reaction

$2Hg^(2+) + Sn^(4+) --> Hg2^(2+) + Sn^(2+)$

$Sn^(4+) + 2e^- -----> Sn^(2+)$ $"electrode potential at anode" = +0.15V$

$2Hg^(2+) -----> Hg2^(+2) + 2e^-$ $"electrode potential at cathode" = +0.9V$

EoCell= EoRed,Cathode - EoRed,Anode

Ecell = 0.9 - 0.15 = +0.75

$triangle G "of change" = -v * F * E^o$

v is the electrons exchanged = 2e- but notice in the equation it is is written -v so take care of that
F is Faraday constant
$E^o$ we know already

Answer will come in joules not in kilojoules but convert it to kilojoules because in exams examiner only accepts kilojoules as answer .

$-2 * 96500"C/mol"^(-1) * 0.75V = -144750J$

$triangle G "of change" = -144750J = -144.75kJ$