Question #e02b1

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Question #e02b1

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Answer 1 · 2017-03-27T00:45:01

Quite simple.

Explanation:

The question stem states that an object is completely immersed in water. Since the object is fully submerged, we have to take the WHOLE volume of the object into account.

First, find the volume by converting cm to m. Then, multiply all sides to get the volume.

$V o l u m e$ $Volume$ = $(0.50 m) (0.01 m) (0.01 m)$ $(0.50m)(0.01m)(0.01m)$ = $5 \cdot 10^{- 5} m^{3}$ $5 * 10^-5 m^3$

To find the buoyant force, use the following equation:

$F_{B} = ρ \cdot V \cdot g$ $F_B = rho*V*g$

Where:
$ρ = density of fluid (1000 \frac{k g}{m^{3}} for water)$ $rho = "density of fluid" (1000 (kg)/m^3 "for water")$
$V = volume of object submerged$ $V = "volume of object submerged"$
$g = gravitational acceleration (9.8 \frac{m}{s^{2}})$ $g = "gravitational acceleration" (9.8 m/s^2)$

Plug in and solve
$F_B = (1000 (kg)/cancelm^3)*(5*10^-5cancelm^3)*(9.8 m/s^2)$
$F_B = 0.49 kg*m/s^2 or 0.49N$

Answer: 0.49N

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Question #e02b1

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