Question #fc0ef

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Question #fc0ef

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Answer 1 · 2017-03-01T13:56:38

$13 \frac{1}{3} minutes$ $13 1/3" minutes"$

Explanation:

$the rest of the mile = 1 - \frac{3}{7} = \frac{4}{7} mile$ $"the rest of the mile "=1-3/7=4/7" mile"$

$Using equivalent fractions in ratio form$ $"Using equivalent fractions in ratio form"$

$\frac{10 mins}{\frac{3}{7} mile} = \frac{x mins}{\frac{4}{7} mile} \leftarrow x to be found$ $("10 mins")/(3/7" mile")=("x mins")/(4/7" mile")larr" x to be found"$

$cross-multiplying$ $color(blue)"cross-multiplying"$

$\frac{3}{7} x = 10 \times \frac{4}{7}$ $3/7x=10xx4/7$

$\Rightarrow \frac{3}{7} x = \frac{40}{7}$ $rArr3/7x=40/7$

multiply both sides by 7

$cancel(7)^1xx(3x)/cancel(7)^1=cancel(7)^1xx40/cancel(7)^1$

$rArr3x=40$

divide both sides by 3

$(cancel(3) x)/cancel(3)=40/3$

$rArrx=40/3=13 1/3$

$"Thus it will take "13 1/3" mins to walk rest of mile"$

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