What are the elemental oxidation states in nitrate anion, $N O_{3}^{-}$ $NO_3^(-)$ ?

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What are the elemental oxidation states in nitrate anion, $N O_{3}^{-}$ $NO_3^(-)$ ?

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Answer 1 · 2017-02-24T16:50:48

The nitrogen centre is formally $N^{+ V}$ $N^(+V)$ in the $nitrate anion.....$ $"nitrate anion....."$ And as is typical, we gots $3 \times O (- I I)$ $3xxO(-II)$ ..

Explanation:

The sum of the oxidation states of the individual elements in a compound ion ALWAYS equals the overall charge on the ion. Here we have the $N O_{3}^{-}$ $NO_3^-$ ion, in which oxygen assumes its usual oxidation state of $- I I$ $-II$ . And thus

$3 \times (- I I) + N_{oxidation state} = - 1$ $3xx(-II)+N_"oxidation state"=-1$

Add $+ 6$ $+6$ to both sides:

$N_{oxidation state} = + V$ $N_"oxidation state"=+V$

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What are the elemental oxidation states in nitrate anion, $N O_{3}^{-}$ $NO_3^(-)$ ?

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Explanation:

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What are the elemental oxidation states in nitrate anion, $N O_{3}^{-}$ $NO_3^(-)$ ?