Question #f3cab

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Question #f3cab

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Answer 1 · 2017-02-24T10:09:53

$\frac{3}{8}$ $3/8$

Explanation:

Probability at least two head means =HHH or HHT or HTH or THH

Probability for {HHH}= $\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{8}$ $1/2*1/2*1/2 = 1/8$

Probability for {HHT}= $\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{8}$ $1/2*1/2*1/2 = 1/8$

Probability for {HTH}= $\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{8}$ $1/2*1/2*1/2 = 1/8$

Probability for {THH}= $\frac{1}{2} \cdot \frac{1}{2} \cdot \frac{1}{2} = \frac{1}{8}$ $1/2*1/2*1/2 = 1/8$

Probability at least two head occur $= \frac{1}{8} + \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{4}{8} = \frac{1}{2}$ $=1/8+1/8+1/8+1/8 =4/8 =1/2$

Probability at least two head occur consecutively is HHH, HHT or THH $= \frac{1}{8} + \frac{1}{8} + \frac{1}{8} = \frac{3}{8}$ $=1/8+1/8+1/8 =3/8$

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Question #f3cab

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