How many oxygen atoms are present in a $120 \cdot g$ $120*g$ mass of $nitric acid$ $"nitric acid"$ ?

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How many oxygen atoms are present in a $120 \cdot g$ $120*g$ mass of $nitric acid$ $"nitric acid"$ ?

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Answer 1 · 2017-02-24T07:35:53

Approx. $3.5 \times 10^{24}$ $3.5xx10^24$ $oxygen atoms......$ $"oxygen atoms......"$

Explanation:

$Moles of nitric acid \equiv \frac{120 \cdot g}{63.01 \cdot g \cdot m o l^{- 1}} = 1.90 \cdot m o l$ $"Moles of nitric acid"-=(120*g)/(63.01*g*mol^-1)=1.90*mol$ .

And thus, given a formula of $H N O_{3}$ $HNO_3$ , there are $3 \times 1.90 \cdot m o l$ $3xx1.90*mol$ $oxygen atoms$ $"oxygen atoms"$ in the given mass of nitric acid.

And since $1 \cdot m o l$ $1*mol$ specifies a quantity of $6.022 \times 10^{23} \cdot m o l^{- 1}$ $6.022xx10^23*mol^-1$ , there are:

$3 \times 1.90 \cdot m o l \times 6.022 \times 10^{23} \cdot m o l^{- 1}$ $3xx1.90*molxx6.022xx10^23*mol^-1$ $oxygen atoms$ $"oxygen atoms"$

$= ? ?$ $=??$ $oxygen atoms............$ $"oxygen atoms............"$

Answer 2 · 2017-02-24T14:09:31

Depends on the concentration.....

Explanation:

If you are thinking of concentrated nitric acid, then it is typically 68% $H N O_{3}$ $HNO_3$ , 32% water. Fuming nitric acid will have $H N O_{3}$ $HNO_3$ content of 86%, and only 14% water.

Oxygen atoms are present in both components, so you'd need to work out the number of moles of both.......

If you take standard conc. nitric acid, then 120 g contains 81.6 g of $H N O_{3}$ $HNO_3$ and 38.4 g of water. This gives you (81.6 / 63.01) = 1.295 moles of $H N O_{3}$ $HNO_3$ and (38.4 / 18.02) = 2.131 moles of water.

Each mole of $H N O_{3}$ $HNO_3$ contains 6.02 x $10^{23}$ $10^23$ molecules each containing an oxygen atom. The same applies to water.

So you have (6.02 x $10^{23}$ $10^23$ x 1.295) + (6.02 x $10^{23}$ $10^23$ x 2.131) = 2.062 x $10^{24}$ $10^24$ oxygen atoms in total.

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How many oxygen atoms are present in a $120 \cdot g$ $120*g$ mass of $nitric acid$ $"nitric acid"$ ?

2 Answers

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Science

Math

Humanities

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How many oxygen atoms are present in a 120⋅g120*g mass of nitric acid"nitric acid"?

2 Answers

Explanation:

Explanation:

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How many oxygen atoms are present in a $120 \cdot g$ $120*g$ mass of $nitric acid$ $"nitric acid"$ ?