Question #586de

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Answer 1 · 2017-03-06T05:40:23

The distance between two parallel mirrors is $l$

The point $O$ is placed at a distance $l/3$ from a mirro.

So the distance of point $O$ from other mirror will be $l=l/3=(2l)/3$

Hence the distance between any two images in the second mirror is $>= (l+l/3-(2l)/3)=(2l)/3$

Hence the distance between any two images in the 1st mirror is $>=(l+(2l)/3-l/3)=(4l)/3$

The distance between the first mimage of first mirror and the first image of second mirror is

$=l/3+l+(2l)/3=2l$

So the distance between any two images can not be $<(2l)/3$