When octane is completely combusted, what is the whole number ratio between the dioxygen reactant, and the product hydrogens?

1 Answer
anor277
Feb 22, 2017

Well, clearly it's #25:18#.

Explanation:

You have the balanced chemical equation:

#C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#

And the stoichiometry precisely specifies that #"25 equiv"# of oxygen gas are required for complete combustion of #"2 equiv"# of #"octane"#, to give #"16 equiv"# of #"carbon dioxide"# and #"18 equiv"# of #"water."#

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