Question #b3cfb

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Question #b3cfb

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Answer 1 · 2018-01-29T17:13:41

$F = 50 N$ $F=50N$

Explanation:

Lets suppose the force of the two kids is called $F_{1}$ $F_1$ . Since they push in the same direction, the force is added.
$F_{1} = 50 N + 50 N$ $F_1=50N+50N$
$F_{1} = 100 N$ $F_1=100N$
Lets suppose the force of the one kid pushing in the opposite direction is called $F_{2}$ $F_2$ .
$F_{2} = 50 N$ $F_2=50N$
Forces in opposite directions have the difference as the resulting force. Lets call this rusulting force $F_{r}$ $F_r$
To calculate $F_{r}$ $F_r$ we subtract $F_{1}$ $F_1$ by $F_{2}$ $F_2$ .
$F_{r} = F_{1} - F_{2}$ $F_r=F_1-F_2$
$F_{r} = 100 N - 50 N$ $F_r=100N-50N$
$F_{r} = 50 N$ $F_r=50N$

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Question #b3cfb

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