How does $sodium oleate$ $"sodium oleate"$ react with $H C l$ $HCl$ ?

Question

How does $sodium oleate$ $"sodium oleate"$ react with $H C l$ $HCl$ ?

1 Answer

Impact of this question

6597 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-02T08:43:20

This is an acid base reaction..........

Explanation:

Here, $sodium oleate$ $"sodium oleate"$ is the conjugate base of a weak acid, and so:

$C_{17} H_{33} C O_{2}^{-}^{+} N a (a q) + H C l (a q) \to C_{17} H_{33} C O_{2} H (a q) + N a C l (a q)$ $C_17H_33CO_2^(-)""^(+)Na(aq) + HCl(aq) rarr C_17H_33CO_2H(aq) + NaCl(aq)$

The product acid, $oleic acid$ $"oleic acid"$ , is the principal component of olive oil: it probably has next to no solubility in water.

Science

Math

Humanities

... and beyond

How does $sodium oleate$ $"sodium oleate"$ react with $H C l$ $HCl$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How does "sodium oleate"sodium oleate"sodium oleate" react with HClHClHCl?

1 Answer

Explanation:

Related questions

Impact of this question

How does $sodium oleate$ $"sodium oleate"$ react with $H C l$ $HCl$ ?