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Question #04063

1 Answer

Mar 3, 2017

#x=1/0.3 log(111)#

Explanation:

#100/1000=1/10=1/(1+999e^(-0.3x))# so

#1+999e^(-0.3x)=10->e^(-0.3x)=9/999=1/111#

finally

#-0.3x=log(1/111)=-log(111)->x=1/0.3 log(111)#

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