How do you solve $- 8 a + 10 = 2 (5 - 4 a)$ $-8a + 10 = 2(5 - 4a)$ ?

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Answer 1 · 2017-02-19T02:57:01

See the entire explanation below:

To deal with the parenthesis you multiply each term within the parenthesis by $2$ $color(red)(2)$ :

$- 8 a + 10 = (2 \times 5) - (2 \times 4 a)$ $-8a + 10 = (color(red)(2) xx 5) - (color(red)(2) xx 4a)$

$- 8 a + 10 = 10 - 8 a$ $-8a + 10 = 10 - 8a$

$- 8 a + 10 = - 8 a + 10$ $-8a + 10 = -8a + 10$

Because both the left and right side of the equation are exactly the same this equation is true for every value of $a$ $a$ .

How do you solve -8a + 10 = 2(5 - 4a)−8a+10=2(5−4a)-8a + 10 = 2(5 - 4a)?