Do highly electronegative atoms form covalent bonds?

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Do highly electronegative atoms form covalent bonds?

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Answer 1 · 2017-02-24T06:47:03

Many elements of high electronegativity will form covalent bonds.....

Explanation:

And I can name three without thinking:

$fluorine; oxygen; and nitrogen$ $"fluorine; oxygen; and nitrogen"$ , which are of course the binuclear molecules $X_{2}$ $X_2$ , $O = O$ $O=O$ , and $N \equiv N$ $N-=N$ .

Electronegativity is conceived to be ability of an atom involved in a chemical bond to polarize electron density towards itself, resulting in a polar bond, where electron density is UNEQUALLY shared. For homonuclear diatomic molecules, given that the elements have EQUAL electronegativity, there should be no charge separation, no polarity in the $element - element$ $"element"-"element"$ bond.

On the other hand for $O F_{2}$ $OF_2$ , which is an isolable molecule, the dipole may be described as $^{+ δ} O F_{2}^{δ -}$ $""^(+delta)OF_2^(delta-)$ . Why?

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Do highly electronegative atoms form covalent bonds?

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