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Question #dcc59

1 Answer

Feb 17, 2017

#b=-2#

Explanation:

According with the conditions we have

#a x^3 + b x^2 + 1=(x-r)(x^2-x-1)#

Equating the coefficients

#{(1 + r=0), (1 + r=0), (1 +b - r=0), (1 - a=0):}#

solving for #a,b,r# we obtain

#a=1,b=-2,r=-1#

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