Question #81c60

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Question #81c60

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Answer 1 · 2017-10-12T23:48:26

The torque is $0.98 N \cdot m$ $0.98 N*m$ .

Explanation:

The weight of the bob is $0.5 k g \cdot 9.8 \frac{m}{s^{2}} = 4.9 N$ $0.5 kg*9.8 m/s^2 = 4.9 N$ .

The component of that weight that is perpendicular to the pendulum rod is $4.9 N \cdot cos 60 = 2.45 N$ $4.9 N*cos60 = 2.45 N$ .

The distance from the pivot to the bob is 0.4 m.

Torque is calculated as follows
$Torque = Perpendicular force \cdot lever length$ $"Torque" = "Perpendicular force"*"lever length"$
$Torque = 2.45 N \cdot 0.4 m = 0.98 N \cdot m$ $"Torque" = 2.45 N*0.4 m = 0.98 N*m$

I hope this helps,
Steve

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Question #81c60

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