Question #46410

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Answer 1 · 2017-07-18T18:34:54

Start with the equation:

$sf(H_2SO_(4(aq))+2KOH_((aq))rarrK_2SO_(4(aq))+2H_2O_((l)))$

This tells us that 1 mole of $sf(H_2SO_4)$ reacts with 2 moles of $sf(KOH)$

$sf(c=n/v)$

$:.$ $sf(n=cxxv)$

$:.$ $sf(n_(H_2SO_4)=cxxv=0.185xx17.7/1000=3.2745xx10^(-3))$

$:.$ $sf(n_(KOH)=2xx3.2745xx10^(-3)=6.549xx10^(-3))$

$sf(v=n/c=(6.549xx10^(-3))/(0.280)=0.023389color(white)(x)"L"=23.4color(white)(x)ml)$