How do you factor ${(x + 3)}^{3} - 4 x - 12$ $(x+3)^3-4x-12$ ?

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How do you factor ${(x + 3)}^{3} - 4 x - 12$ $(x+3)^3-4x-12$ ?

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Answer 1 · 2017-02-19T14:28:30

${(x + 3)}^{3} - 4 x - 12 = (x + 1) (x + 5) (x + 3)$ $(x+3)^3-4x-12 = (x+1)(x+5)(x+3)$

Explanation:

${(x + 3)}^{3} - 4 x - 12 = {(x + 3)}^{3} - 4 (x + 3)$ $(x+3)^3-4x-12 = (x+3)^3-4(x+3)$

${(x + 3)}^{3} - 4 x - 12 = ({(x + 3)}^{2} - 4) (x + 3)$ $color(white)((x+3)^3-4x-12) = ((x+3)^2-4)(x+3)$

${(x + 3)}^{3} - 4 x - 12 = (x^{2} + 6 x + 9 - 4) (x + 3)$ $color(white)((x+3)^3-4x-12) = (x^2+6x+9-4)(x+3)$

${(x + 3)}^{3} - 4 x - 12 = (x^{2} + 6 x + 5) (x + 3)$ $color(white)((x+3)^3-4x-12) = (x^2+6x+5)(x+3)$

${(x + 3)}^{3} - 4 x - 12 = (x + 1) (x + 5) (x + 3)$ $color(white)((x+3)^3-4x-12) = (x+1)(x+5)(x+3)$

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How do you factor ${(x + 3)}^{3} - 4 x - 12$ $(x+3)^3-4x-12$ ?

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How do you factor (x+3)3−4x−12(x+3)^3-4x-12 ?

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Explanation:

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How do you factor ${(x + 3)}^{3} - 4 x - 12$ $(x+3)^3-4x-12$ ?