Question #248d8

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SCooke
Feb 11, 2017

Silver nitrate. 9.11g Silver chloride.

Explanation:

First convert the given quantities of compounds to moles. Then apply the balanced equation. 10.8g #AgNO_3# is
#(10.8g / (170g/(mol)))# = 0.0635 moles #AgNO_3# .

0.1276L * 0.500mol/L = 0.0638 moles #CaCl_2#.

So, we have almost equal molar quantities of each reactant, but the reaction equation shows that TWO moles of #AgNO_3# are needed to react with ONE mole of #CaCl_2#. Therefore, the #AgNO_3# is the limiting reagent, leaving half of the chloride in solution.

The maximum products that can be formed are ONE mole of AgCl for every ONE mole of #AgNO_3# . Because we already determined that it is the limiting reagent, it will be completely reacted, producing 0.0635 moles of silver chloride.

0.0635mol * 143.5g/mol = 9.11g AgCl.

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