Question #c045e

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Question #c045e

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Answer 1 · 2017-07-08T10:45:02

option (2)

Explanation:

#stackrel0Cl_2+stackrel(+1)Na stackrel(-2) O stackrel(+1)H->stackrel(+1)Na stackrel(+5)Clstackrel(-2)O_3+stackrel(+1)Na stackrel(-1)Cl+stackrel(+1)H_2stackrel(-2)O#

This is a disproportionation reaction where same element #Cl# gets oxidised as well as reduced.

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Question #c045e

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