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Question #ed5b1

1 Answer

May 25, 2017

# 1/26+(5/26)i.#

Explanation:

Let, #z=i/(5+i).#

# rArr z=i/(5+i)xx(5-i)/(5-i),#

#=(5i-i^2)/(5^2-i^2),#

#=(5i-(-1))/(25-(-1)),#

#=(1+5i)/26,#

# :. z=1/26+(5/26)i.#

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