What is the #"molality"# of a #30g# mass of sodium hydroxide dissolved in a #100g# mass of water?

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Answer 1 · 2017-06-06T18:07:59

#"Molality"=7.5*mol*kg^-1#

#"Molality"="Moles of solute"/"Kilograms of solute"#

And here we have #30*g# #NaOH# solute..........

So #"Molality"=((30*g)/(40.00*g*mol^-1))/(100*gxx10^-3*g*kg^-1)=7.5*mol*kg^-1.#

What is the #"molality"# of a #30*g# mass of sodium hydroxide dissolved in a #100*g# mass of water?