Question #2041c
1 Answer
The maximum area is
radius of the semicircle is
16/(4 + pi) (~~ 2.24)
rectangular window is16/(4+pi) xx 32/(4 + pi) (~~ 2.24 xx4.48)
Explanation:
Let us set up the following variables:
{(r, "Radius of the semicircle","(feet)"), (h, "Height of the rectangular window","(feet)"), (A, "Total area enclosed by the window", "(sq feet)") :}
Our aim is to find
The total perimeter is that of
16 = (h + 2r + h) + (1/2)(2pir)
\ \ \ = 2r + 2h + pi r
:. 2h = 16 - 2r - pi r
:. \ \ h = 1/2(16 - 2r - pi r)
And the total Area is that of a rectangle and a semicircle:
A = (h)(2r) + (1/2)(pir^2)
\ \ \ = 2hr + 1/2 pi r^2
\ \ \ = 2(1/2(16 - 2r - pi r))r + 1/2 pi r^2
\ \ \ = 16r - 2r^2 - pi r^2 + 1/2 pi r^2
\ \ \ = 16r - 2r^2 - 1/2 pi r^2
We now have the Area,
(dA)/(dr) = 16 - 4r - pi r
At a critical point we have
16 - 4r - pi r = 0
:. \ \ \ \ 4r + pi r = 16
:. \ \ \ r(4 + pi) = 16
:. \ \ \ \ \ \ \ \ \ \ \ \ \ \ \r = 16/(4 + pi) (~~ 2.24)
With this value of
A = 16(16/(4 + pi)) - 2(16/(4 + pi))^2 - 1/2 pi (16/(4 + pi))^2
\ \ \ = 128/(4 + pi) (~~ 17.92)
And:
h = 1/2(16 - 2(16/(4 + pi)) - pi (16/(4 + pi)))
\ \ = 16/(4+pi) (~~ 2.24)
We can visually verify that this corresponds to a maximum by looking at the graph of
graph{16x - 2x^2 - 1/2 pi x^2 [-5, 10, -5, 22]}
And also check that the perimeter is correct:
P = 2r + 2h + pi r
\ \ = 2(16/(4 + pi)) + 2(16/(4 + pi)) + pi(16/(4 + pi))
\ \ = 16