Question #2041c

1 Answer
Feb 6, 2017

The maximum area is 128/(4 + pi) (~~ 17.92). This occurs when:

radius of the semicircle is 16/(4 + pi) (~~ 2.24)
rectangular window is 16/(4+pi) xx 32/(4 + pi) (~~ 2.24 xx4.48)

Explanation:

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Let us set up the following variables:

{(r, "Radius of the semicircle","(feet)"), (h, "Height of the rectangular window","(feet)"), (A, "Total area enclosed by the window", "(sq feet)") :}

Our aim is to find A(h,r), as a function of a single variable and to maximize the total area, A, wrt that variable (It won't matter which variable we do this with as we will get the same result). ie we want a critical point of A wrt the variable.

The total perimeter is that of 3 sides of the rectangle and the semicircle; we are told that this perimeter is 16 feet

16 = (h + 2r + h) + (1/2)(2pir)
\ \ \ = 2r + 2h + pi r

:. 2h = 16 - 2r - pi r
:. \ \ h = 1/2(16 - 2r - pi r)

And the total Area is that of a rectangle and a semicircle:

A = (h)(2r) + (1/2)(pir^2)
\ \ \ = 2hr + 1/2 pi r^2
\ \ \ = 2(1/2(16 - 2r - pi r))r + 1/2 pi r^2
\ \ \ = 16r - 2r^2 - pi r^2 + 1/2 pi r^2
\ \ \ = 16r - 2r^2 - 1/2 pi r^2

We now have the Area, A, as a function of a single variable r, so differentiating wrt x we get:

(dA)/(dr) = 16 - 4r - pi r

At a critical point we have (dA)/(dr) =0 =>

16 - 4r - pi r = 0
:. \ \ \ \ 4r + pi r = 16
:. \ \ \ r(4 + pi) = 16
:. \ \ \ \ \ \ \ \ \ \ \ \ \ \ \r = 16/(4 + pi) (~~ 2.24)

With this value of r we have:

A = 16(16/(4 + pi)) - 2(16/(4 + pi))^2 - 1/2 pi (16/(4 + pi))^2
\ \ \ = 128/(4 + pi) (~~ 17.92)

And:

h = 1/2(16 - 2(16/(4 + pi)) - pi (16/(4 + pi)))
\ \ = 16/(4+pi) (~~ 2.24)

We can visually verify that this corresponds to a maximum by looking at the graph of y=A(r):

graph{16x - 2x^2 - 1/2 pi x^2 [-5, 10, -5, 22]}

And also check that the perimeter is correct:

P = 2r + 2h + pi r
\ \ = 2(16/(4 + pi)) + 2(16/(4 + pi)) + pi(16/(4 + pi))
\ \ = 16