Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

Question #f78be

1 Answer

Feb 5, 2017

Approx. #90*g# chlorine gas are required.

Explanation:

#Fe+3/2Cl_2 rarr FeCl_3#

#"Moles of ferric chloride"# #=# #(140*g)/(162.2*g*mol^-1)=0.863*mol.#

And given the stoichiometry we need #3/2xx2xx35.45*g*mol^-1xx0.863*mol# #=# #?*g# #*Cl_2#

Related questions

See all questions in Stoichiometry

Impact of this question

1557 views around the world

You can reuse this answer
Creative Commons License