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Question #3cdea

1 Answer

A. S. Adikesavan

Feb 5, 2017

#sec^2(x+pi/4)#

Explanation:

#y=(1+tanx)/(1-tanx)=(tan(pi/4)+tanx)/(1-tan(pi/4)tanx)#

#=tan(x+pi/4)#.

So, #(dy)/(dx)=sec^2(x+pi/4)#

If y is cosx+tanx-sinx, it is direct, and

#y'=-sinx+sec^2x-cosx#

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