Question #cb30b

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Question #cb30b

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Answer 1 · 2017-03-06T16:50:49

(a) Using the kinematic expression
$v^2-u^2=2as$ and inserting given values in SI units we get
$v^2-(7.0)^2=2xx0.71xx1033$
$v^2=49+2xx0.71xx1033$
$v=sqrt(49+2xx0.71xx1033)=38.9ms^-1$ , rounded to one decimal plave

(b) We can use the following kinematic expression here
$v=u+at$
as velocity $v$ is attained after moving a distance of $1.033km$
$=>t=(v-u)/a$ and inserting given values we get
$t=(38.9-7.0)/0.71=45s$ rounded to nearest second.

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