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Simplyfy #ln(1/90)# in terms of ln?

1 Answer

Mar 25, 2017

#-[color(white)(.)2ln(3)+ln(2)+ln(5)color(white)(.)]#

Explanation:

This is the same as #ln(1)-ln(90)#

but #ln(1)=0# so we only need to consider #-ln(90)#

Lets consider #90->3xx30=3xx3xx10 = 3xx3xx2xx5#

So we have:

#-[color(white)(.)2ln(3)+ln(2)+ln(5)color(white)(.)]#

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