If the solubility of a gas is 0.5*g*L^-1 at "1 bar" gas pressure, what will be its solubility at "3 bar" gas pressure?

1 Answer
anor277
Feb 2, 2017

Approx. 1.5*g*L^-1...........

Explanation:

"Henry's Law" relates to the solubility of a gas in a liquid. At a given temperature, the solubility of the gas is proportional to the partial pressure of the gas above the liquid.

i.e. "Gas solubility" prop P_"gas"

Or, "Gas solubility" = k_"P"P_"gas", where k_"P" is the socalled "Henry's Law gas constant".

And thus, P_"initial solubility"=kxx1*"bar"=0.5*g*L^-1.

P_"solubility at elevated pressure"=kxx3*"bar"=1.5*g*L^-1.

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