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If $cosa=m$ , what is $sin(a-pi/2)$ ?

1 Answer

Shwetank Mauria

Feb 2, 2017

$sin(a-pi/2)=-m$

Explanation:

We can use two formulas here. One $sin(-A)=-sinA$ and $sin(pi/2-A)=cosA$

Hence $sin(a-pi/2)=sin(-(pi/2-a))$

= $-sin(pi/2-a)=-cosa=-m$

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