Question #41939

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Answer 1 · 2017-02-11T15:54:18

$"(i)"$ $"H"_2"C=CH"_2 + "H"_2 rarr"H"_3"C-CH"_3$

And this is a (simple?) hydrogenation reaction.

For methane and chlorine, normally we would invoke photolysis:

$"(ii)"$ $"CH"_4 + "Cl"_2 +hnu rarr "H"_3"CCl" + "HCl"$

Possibly, you would get a mess under conditions of thermolysis.

The last rxn is a substitution process:

$"(iii) " "H"_3"CC""H"_2"Br(l)" "+ KOH(aq)" rarr "H"_3"CCH"_2"OH(l)" "+ KBr(s)"darr$

The deposition of potassium bromide, a stable salt, provides a thermodynamic driving force to the reaction.