What is the mass of 4.70xx10^224.70×1022 individual "sulfur atoms"sulfur atoms?

1 Answer
anor277
Feb 10, 2017

Approx. 2.5*g2.5⋅g

Explanation:

We know that 6.022xx10^236.022×1023 individual sulfur atoms have a mass of 32.06*g32.06⋅g. How do we know this?

And thus we work out the product:

32.06*g*mol^-1xx(4.70xx10^22cancel" sulfur atoms ")/(6.022xx10^23cancel" sulfur atoms "mol^-1)

=??*mol

Note that as far as anyone knows, sulfur, as the yellow powder, is the S_8 molecule. The size of the molecule probably explains its extreme insolubility in most solvents.

Related questions
See all questions in The Mole
Impact of this question
1717 views around the world
You can reuse this answer
Creative Commons License