How do you simplify $((m^2)^2z^3zd)/(mz^5d^3)$ ?

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Answer 1 · 2017-02-01T01:37:15

$(m^3)/(zd^2)$

Simplify $((m^2)^2z^3zd)/(mz^5d^3)$ .

First apply power rule $(b^m)^n=b^(m*n)$ .

$(m^((2*2))z^3zd)/(mz^5d^3)$

$(m^4z^3zd)/(mz^5d^3)$

Apply product rule $a^ma^n=a^((m+n)).$
(Reminder: $b=b^1$ ).

$(m^4z^3z^1d)/(mz^5d^3)$

$(m^4z^((3+1))d)/(mz^5d^3)$

Simplify.

$(m^4z^4d)/(mz^5d^3)$

Apply quotient rule $a^m/a^n=a^((m-n))$ .

$m^((4-1))z^((4-5))d^((1-3))$

Simplify.

$m^3z^(-1)d^(-2)$

Apply negative exponent rule $a^(-m)=1/a^m$ .

$(m^3)/(zd^2)$

How do you simplify ((m^2)^2z^3zd)/(mz^5d^3)((m^2)^2z^3zd)/(mz^5d^3)?