How many atoms in a $9.6 \cdot g$ $9.6*g$ mass of sulfur?

Question

How many atoms in a $9.6 \cdot g$ $9.6*g$ mass of sulfur?

1 Answer

Impact of this question

16090 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-28T06:02:29

$Number of atoms$ $"Number of atoms"$ $=$ $=$ $\frac{Mass}{Molar mass} \times Avogadro's number.$ $"Mass"/"Molar mass"xx"Avogadro's number."$

Explanation:

$Atoms of sulfur$ $"Atoms of sulfur"$ $=$ $=$ $\frac{9.60 \cdot g}{32.06 \cdot g \cdot m o l^{- 1}} \times 6.022 \times 10^{23} \cdot m o l^{- 1}$ $(9.60*g)/(32.06*g*mol^-1)xx6.022xx10^23*mol^-1$ .

Because the units all cancel out, the answer is clearly a number, $≅ 2 \times 10^{23}$ $~=2xx10^23$ as required.

Science

Math

Humanities

... and beyond

How many atoms in a $9.6 \cdot g$ $9.6*g$ mass of sulfur?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How many atoms in a 9.6*g9.6⋅g9.6*g mass of sulfur?

1 Answer

Explanation:

Related questions

Impact of this question

How many atoms in a $9.6 \cdot g$ $9.6*g$ mass of sulfur?