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Question #6fd74

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Jan 25, 2017

#angleRQP=45^@#
#angleSPR=50^@#
#anglePSR=80^@#

Explanation:

enter image source here

Given that #SP=SR, and angleSRP=50^@#,
#=> DeltaSRP# is isoceles, #=> angleSPR=angleSRP=50^@#
#=>anglePSR=180-50-50=80^@#

As #PQ# is parallel to #SR, => angleRPQ=angleSRP=50^@#
#=> angleRQP=180-85-50=45^@#

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