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Question #d67e3

1 Answer

Jan 23, 2017

#1#.

Explanation:

Since, #x:y=1:2," let us take, "m/_x=theta, m/_y=2theta#.

But, #x & y" are complementary, "m/_x+m/_y=90^@#.

#:. theta+2theta=90^@ rArr theta=30^@#

# rArr m/_x=30^@, m/_y=60^@#.

#rArr sinx+cosy=sin30^@+cos60^@=1/2+1/2=1#.

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