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Answer 1 · 2017-01-23T07:57:52

#4C_2H_3Cl_3+11O_2→ 8CO_2+ 6H_2O + 6Cl_2#

Above equation suggests that the #CO_2 and Cl_2# will be produced in the mole ratio #8:6=4:3#

So ratio of their masses will be
#=(4xx"molar mass of " CO_2)/(3xx"molar mass of "Cl_2)#

#=(4*44g"/mol")/(3*71g"/mol")#

#=176/213#

If xg #Cl_2# is produced on production of 59.5g #CO_2# then we can write
#59.5/x=176/213#

#=>x=(59.5xx213)/176g~~72g#